Solving Word Problems With Quadratic Equations

Solving Word Problems With Quadratic Equations-81
Had the speed been 15 km/hour more it would have taken 30 minutes less for the journey. Solution(6) From a group of 2x black bees , square root of half of the group went to a tree.

To create this article, volunteer authors worked to edit and improve it over time.

We will discuss here how to solve the word problems using quadratic formula. If the speed of the stream is 1.5 km/h, find the speed of the boat in still water.

Then, the speed of the boat up the stream (or against the stream) = (x - \(\frac\)) km/hour, and the speed of the boat down the stream (or along the stream) = (x \(\frac\)) km/hour.

Therefore, time taken to travel 10 km up the stream = \(\frac\) hours and time taken to travel 5 km down the stream = \(\frac\) hours.

The two galleries are separated by the distance of 70 m.

Where should a person stand for hearing the same intensity of the singers voice?(Hint: The ratio of the sound intensity is equal to the square of the ratio of their corresponding distances).Solution There is a square field whose side is 10 m.A square flower bed is prepared in its centre leaving a gravel path all round the flower bed.The total cost of laying the flower bed and gravelling the path at ₹3 and ₹4 per square metre respectively is ₹364. Solution(9) Two women together took 100 eggs to a market, one had more than the other. sorts of word problems, it is usually helpful to draw a picture.Since I'll be cutting equal-sized squares out of all of the corners, and since the box will have a square bottom, I know I'll be starting with a square piece of cardboard.The remaining two got caught up in a fragrant lotus. Solution(7) Music is been played in two opposite galleries with certain group of people.In the first gallery a group of 4 singers were singing and in the second gallery 9 singers were singing.Therefore, from the question,\(\frac\) \(\frac\) = 6⟹ \(\frac\) \(\frac\) = 6⟹ \(\frac\) \(\frac\) = 3⟹ \(\frac\) = 3⟹ \(\frac\) = 3⟹ \(\frac\) = 1⟹ 10x 5 = 4x\(^\) – 9⟹ 4x\(^\) – 10x – 14 = 0⟹ 2x\(^\) -5x – 7 = 0⟹ 2x\(^\) - 7x 2x - 7= 0⟹ x(2x - 7) 1(2x - 7) = 0⟹ (2x - 7)(x 1) = 0⟹ 2x - 7 = 0 or x 1 = 0⟹ x = \(\frac\) or x = -1But speed cannot be negative.So, x = \(\frac\) = 3.5Therefore, the speed of the board in still water is 3.5 km/h.

SHOW COMMENTS

Comments Solving Word Problems With Quadratic Equations

The Latest from www.fotofc.ru ©