Using Equations To Solve Word Problems

Using Equations To Solve Word Problems-38
Many students find solving algebra word problems difficult.

Many students find solving algebra word problems difficult.The best way to approach word problems is to “divide and conquer”.Worked-out word problems on linear equations with solutions explained step-by-step in different types of examples. Solution: Then the other number = x 9Let the number be x. Therefore, x 4 = 2(x - 5 4) ⇒ x 4 = 2(x - 1) ⇒ x 4 = 2x - 2⇒ x 4 = 2x - 2⇒ x - 2x = -2 - 4⇒ -x = -6⇒ x = 6Therefore, Aaron’s present age = x - 5 = 6 - 5 = 1Therefore, present age of Ron = 6 years and present age of Aaron = 1 year.5. Then the other multiple of 5 will be x 5 and their sum = 55Therefore, x x 5 = 55⇒ 2x 5 = 55⇒ 2x = 55 - 5⇒ 2x = 50⇒ x = 50/2 ⇒ x = 25 Therefore, the multiples of 5, i.e., x 5 = 25 5 = 30Therefore, the two consecutive multiples of 5 whose sum is 55 are 25 and 30. The difference in the measures of two complementary angles is 12°. ⇒ 3x/5 - x/2 = 4⇒ (6x - 5x)/10 = 4⇒ x/10 = 4⇒ x = 40The required number is 40.

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According to the question; Ron will be twice as old as Aaron. Complement of x = 90 - x Given their difference = 12°Therefore, (90 - x) - x = 12°⇒ 90 - 2x = 12⇒ -2x = 12 - 90⇒ -2x = -78⇒ 2x/2 = 78/2⇒ x = 39Therefore, 90 - x = 90 - 39 = 51 Therefore, the two complementary angles are 39° and 51°9. If the table costs $40 more than the chair, find the cost of the table and the chair. Solution: Let the number be x, then 3/5 ᵗʰ of the number = 3x/5Also, 1/2 of the number = x/2 According to the question, 3/5 ᵗʰ of the number is 4 more than 1/2 of the number.

Solution: Let the breadth of the rectangle be x, Then the length of the rectangle = 2x Perimeter of the rectangle = 72Therefore, according to the question2(x 2x) = 72⇒ 2 × 3x = 72⇒ 6x = 72 ⇒ x = 72/6⇒ x = 12We know, length of the rectangle = 2x = 2 × 12 = 24Therefore, length of the rectangle is 24 m and breadth of the rectangle is 12 m. Then Aaron’s present age = x - 5After 4 years Ron’s age = x 4, Aaron’s age x - 5 4. Then the cost of the table = $ 40 x The cost of 3 chairs = 3 × x = 3x and the cost of 2 tables 2(40 x) Total cost of 2 tables and 3 chairs = $705Therefore, 2(40 x) 3x = 70580 2x 3x = 70580 5x = 7055x = 705 - 805x = 625/5x = 125 and 40 x = 40 125 = 165Therefore, the cost of each chair is $125 and that of each table is $165. If 3/5 ᵗʰ of a number is 4 more than 1/2 the number, then what is the number?

This include geometry word problems Involving Perimeters, Involving Areas and Involving Angles Integer Problems involve numerical representations of word problems.

The integer word problems may Involve 2 Unknowns or may Involve More Than 2 Unknowns Interest Problems involve calculations of simple interest.

Ratio Problems require you to relate quantities of different items in certain known ratios, or work out the ratios given certain quantities.

This could be Two-Term Ratios or Three-Term Ratios Symbol Problems Variation Word Problems may consist of Direct Variation Problems, Inverse Variation Problems or Joint Variation Problems Work Problems involve different people doing work together at different rates.

Then, we need to solve the equation(s) to find the solution(s) to the word problems.

Translating words to equations How to recognize some common types of algebra word problems and how to solve them step by step: Age Problems usually compare the ages of people.

Coin Problems deal with items with denominated values.

Similar word problems are Stamp Problems and Ticket Problems.

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